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- The compileall script is used to compile to python bytecode all the modules.
- However, it relies on the struct package that is not built for the host
- python, thus crashing at execution when compiling the target python.
- When compiling, the removed code block is never executed, so we can safely
- remove it, removing in the same time the dependency on struct.
- Patch by Maxime Ripard <ripard@archos.com>
- Index: Python-2.7/Lib/compileall.py
- ===================================================================
- --- Python-2.7.orig/Lib/compileall.py (révision 84276)
- +++ Python-2.7/Lib/compileall.py (copie de travail)
- @@ -14,7 +14,6 @@
- import os
- import sys
- import py_compile
- -import struct
- import imp
-
- __all__ = ["compile_dir","compile_file","compile_path"]
- @@ -83,17 +82,6 @@
- if os.path.isfile(fullname):
- head, tail = name[:-3], name[-3:]
- if tail == '.py':
- - if not force:
- - try:
- - mtime = int(os.stat(fullname).st_mtime)
- - expect = struct.pack('<4sl', imp.get_magic(), mtime)
- - cfile = fullname + (__debug__ and 'c' or 'o')
- - with open(cfile, 'rb') as chandle:
- - actual = chandle.read(8)
- - if expect == actual:
- - return success
- - except IOError:
- - pass
- if not quiet:
- print 'Compiling', fullname, '...'
- try:
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