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Makefile: remove $(HOST_DIR)/usr from BR_PATH

Now $(HOST_DIR)/usr is a symlink to $(HOST_DIR), it makes no sense to
still have it in BR_PATH.

Signed-off-by: Arnout Vandecappelle (Essensium/Mind) <arnout@mind.be>
Reviewed-by: Romain Naour <romain.naour@smile.fr>
Signed-off-by: Thomas Petazzoni <thomas.petazzoni@free-electrons.com>
Arnout Vandecappelle 8 роки тому
батько
коміт
4c8872d8e7
1 змінених файлів з 1 додано та 1 видалено
  1. 1 1
      Makefile

+ 1 - 1
Makefile

@@ -440,7 +440,7 @@ TAR_OPTIONS = $(call qstrip,$(BR2_TAR_OPTIONS)) -xf
 HOST_DIR := $(call qstrip,$(BR2_HOST_DIR))
 
 # Quotes are needed for spaces and all in the original PATH content.
-BR_PATH = "$(HOST_DIR)/bin:$(HOST_DIR)/sbin:$(HOST_DIR)/usr/bin:$(HOST_DIR)/usr/sbin:$(PATH)"
+BR_PATH = "$(HOST_DIR)/bin:$(HOST_DIR)/sbin:$(PATH)"
 
 # Location of a file giving a big fat warning that output/target
 # should not be used as the root filesystem.